Gay-Lussac's Law describes the relationship between the pressure and temperature of a gas at constant volume. It can be expressed mathematically as:
center;">P1/T1 = P2/T2
If a gas has an initial pressure of 2 atm at a temperature of 300 K, what will be its pressure if the temperature is increased to 400 K?
Using the formula P1/T1 = P2/T2, we can solve for P2:
center;">2 atm / 300 K = P2 / 400 K
center;">P2 = (2 atm * 400 K) / 300 K
center;">P2 = 2.67 atm
So, the pressure of the gas at 400 K will be 2.67 atm.