Isolate the sine function: \(x = \sin^{-1}\left(\frac{1}{2}\)\)
Using the unit circle or reference angles, we find the solutions \(x = \frac{\pi}{6} + 2n\pi\) and \(x = \frac{5\pi}{6} + 2n\pi\), where \(n\) is an integer.
The general solution is \(x = \frac{\pi}{6} + 2n\pi\) and \(x = \frac{5\pi}{6} + 2n\pi\).