Factor the trinomial \( 2x^2 + 11x + 5 \).
We can factor this trinomial by finding two numbers that multiply to \( 2 \times 5 = 10 \) and add to 11. These numbers are 10 and 1.
So the factored form is \( (2x+1)(x+5) \).
```- **Problem 2:** Solve the equation \( x^2 - 4x - 5 = 0 \) by factoring. ```htmlSolve the equation \( x^2 - 4x - 5 = 0 \) by factoring.
We first factor the trinomial to \( (x-5)(x+1) \).
Setting each factor equal to zero gives us the solutions \( x = 5 \) and \( x = -1 \).
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