P1 / T1 = P2 / T2
Where:2.0 atm / 300 K = P2 / 350 K
Solving for P2:P2 = (2.0 atm * 350 K) / 300 K
P2 = 2.33 atm
Therefore, the pressure of the gas at 350 K will be 2.33 atm.2. A gas at a pressure of 3.0 atm and a temperature of 400 K is cooled until its pressure is 2.0 atm. What is the final temperature of the gas, assuming the volume remains constant? Using Gay-Lussac's Law: P1 / T1 = P2 / T23.0 atm / 400 K = 2.0 atm / T2
Solving for T2:T2 = (2.0 atm * 400 K) / 3.0 atm
T2 = 266.67 K
.